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Math Help - How 'bout this integral

  1. #1
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    Unhappy How 'bout this integral

    Perform the antidifferentiation:

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  2. #2
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by ^_^Engineer_Adam^_^ View Post
    Integrate:


    We proceed by substitution:

    we have int{(1/t - 1)(1/t^2)}dt

    let u = 1/t - 1
    => du = -t^-2 dt
    => -du = t^-2 dt

    so our integral becomes

    -int{sqrt(u)}du = - (2/3)u^(3/2) + C
    .....................= (-2/3)(1/t - 1)^(3/2) + C
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