1/2aX^2 +bXY + h'(y) = bX + cY, where a,b,c are constants. the answer is h'(y) = cY can anyone show me how this is so? i can't understand how this is the value of h'(y)..
Last edited by greencheeseca; February 15th 2010 at 05:07 AM. Reason: solved
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already solved. Originally Posted by greencheeseca 1/2aX^2 +bXY + h'(y) = bX + cY, where a,b,c are constants. the answer is h'(y) = cY can anyone show me how this is so? i can't understand how this is the value of h'(y)..
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