find the polynomial ft f(x) with the smallest degree so that
$\displaystyle \lim_{x->1}\frac{f(x)}{x-1}\$=1
and
$\displaystyle \lim_{x->2}\frac{f(x)}{x-2}\$=2
and
$\displaystyle \lim_{x->3}\frac{f(x)}{x-3}\$=3
pls how should i assume the ft?
find the polynomial ft f(x) with the smallest degree so that
$\displaystyle \lim_{x->1}\frac{f(x)}{x-1}\$=1
and
$\displaystyle \lim_{x->2}\frac{f(x)}{x-2}\$=2
and
$\displaystyle \lim_{x->3}\frac{f(x)}{x-3}\$=3
pls how should i assume the ft?