f(x)= (3-x)(5+x)/x(x+3)^2

x<-5 pos or neg?

-5<x<-3 pos or neg?

-3<x<0 pos or neg

0<x<3 pos or neg

x>3 pos or neg

The zeros of the eq are, 3 , -5, 0, and -3. But after that, I have no idea how to finish the question.):

Help would be much appreciated!

Thnx~