Hello, here is my problem.

Find the volume of the solid generated by revolving the region bounded by the curves y = -x^2+6 and y = 3x+2, about the line y=8. Now I'm only suppose to setup but I just want to make sure I'm doing this correctly. I can use any method and in this case I picked the washer method.

So, here is what I have R(x) = 8 - (3x+2), and r(x) = 8-(-x^2+6) and my integral is

Pi * integral[(6-3x)^2-(3+x^2)^2]dx from -4, to 1. Is this the correct way to go about doing this?