# Thread: Trigonometric Inegrals: Volume help

1. ## Trigonometric Inegrals: Volume help

Let R be the region enclosed by the curves y=6sin2x and y=6 over the segment [ π/2,3π/2]. Find the volume of the solid that is obtained by rotating R about the line y=−1.1.

i get V=451.7359646 but its wrong..

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then i found the antiderivative of sin4x and sin2x and got the final answer of the Volume. what did i mess up on?

2. Originally Posted by Baatata
Let R be the region enclosed by the curves y=6sin2x and y=6 over the segment [ π/2,3π/2]. Find the volume of the solid that is obtained by rotating R about the line y=−1.1.

i get V=451.7359646 but its wrong..

== >

then i found the antiderivative of sin4x and sin2x and got the final answer of the Volume. what did i mess up on?
Is your function $6Sin^2x$ or $6Sin2x$ ?

Your calculations suggest it is $6Sin^2x$

I get 426.6
Can you show your calculations for your integrals of the powers of Sinx ?