200(1-0.956e^(-.18t)=L(t)

L=length

t=time

(a) find the rate of change of the length as a function of time

ok so i redid the derivative and got 34.416e^(-.18t) then do i take f''(t)?

(b) what is the rate when t=2

enter in 2 for t in the derivative

(c)when will the rate of growth =6

make derivative =6

so am i on the right path?