nevermind i figured it out
200(1-0.956e^(-.18t)=L(t)
L=length
t=time
(a) find the rate of change of the length as a function of time
ok so i redid the derivative and got 34.416e^(-.18t) then do i take f''(t)?
(b) what is the rate when t=2
enter in 2 for t in the derivative
(c)when will the rate of growth =6
make derivative =6
so am i on the right path?