Hello,

dy/dx = ∫(d²y/dx²)dx therefore:

dy/dx = ∫(2-4x)dx = 2x - 2x² +C

y = ∫(dy/dx)dx therefore:

y = ∫(2x - 2x² + C)dx = x² - 2/3*x³ + Cx + D

Plug in the coordinates of the points you know:

(-1, 3): 1 + 2/3 - C + D = 3

(0, 2): 0 - 0 + 0 + D = 2 Plug in this value into the first equation:

1 + 2/3 - C + 2 = 3 and solve for C. C = 2/3

the complete equation is:

y = -2/3*x³ + x² + 2/3*x + 2

EB