sorry misread post
Find an equation of the tangent line to the curve at the given point. y = 6 sec x
P = (π/3, 12)
I know that the first step is taking the derivative of 6 sec x, but i dont quit know how to deal with the pi over 3 when i use it in the derivative to find the slope.
File:Unit circle angles.svg - Wikipedia, the free encyclopedia
You probably have studied a version of this in a trig course.
The coordinate corresponding to is . That means and . We notice that and and we can find each of those values in exact form. (You can also now see where the term comes from.)