Can anyone help me with this problem?

Integrate ln[(x^2)+2] dx

Can this be done by integration by parts?

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- March 22nd 2007, 01:31 PMCsou090490Integration
Can anyone help me with this problem?

Integrate ln[(x^2)+2] dx

Can this be done by integration by parts? - March 22nd 2007, 02:07 PMThePerfectHacker
I can do the derivation but it is really long.

Just go here if you want the answer without the derivation. - March 22nd 2007, 02:40 PMSoroban
Hello, Csou090490!

Quote:

∫ ln[x² + 2] dx

Can this be done by integration by parts? . Yes!

. . . . . . . . .2x

. .du .= . -------- dx . . . .v .= .x

. . . . . . . x² + 2

. . . . . . . . . . . . . . . . . . . . . . .x²

We have: . x·ln(x² + 2) - 2 ∫ -------- dx

. . . . . . . . . . . . . . . . . . . . .x² + 2

. . . . . . . . . . . . . . . . . . . 2

Divide that fraction: .1 - --------

. . . . . . . . . . . . . . . . . .x² + 2

. . . and go for it!