1. ## limit of sum

$\sum_{i=0}^n\frac{4}{n}*({1+(i/4n)})^4\$

as n goes infinite

2. Note that the sum is the Riemann Sum of f(x) = (1+x/16)^4

on the interval 0 to 4

So the sum = integral[(1+x/16)^4dx] from 0 to 4

3. Originally Posted by Calculus26
Note that the sum is the Riemann Sum of f(x) = (1+x/16)^4

on the interval 0 to 4

So the sum = integral[(1+x/16)^4dx] from 0 to 4
i think the interval is 1 to 5?? is it right??

4. No it is 0 to 4 see the attachment where I use mathcad to evaluate the sum and the integral to verify my results.

Why do you think the interval would be 1 to 5 ?