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Math Help - Review Sheet

  1. #1
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    Red face Review Sheet

    Hello!
    I am in dire need of help! I just recieved this Review Sheet that I completely do not understand.
    I believe some of the stuff is from last year, Pre-Calc. and I'm completely blank as far as that goes. I'm currently a high school students taking the class for AP-credit and for some reason I can't remember anything from class and/or review books.

    Please if you can, help me out by explaining what and how I need to do these problems.
    I have another review sheet but I believe if I understand this one I will be able to do the other one on my own.





    Thank you!
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  2. #2
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    your 1st question involves an understanding of finding critical points of a function by finding its derivative. your second question simply involves the following points:acceleration is given by the derivative of velocity and the velocity is given by the derivative of the postion.
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  3. #3
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    1. (a) use the facts that f'(-1) = 0 and f''(-2) = 0 to solve for a and b.

    (b) straight forward problem, once you find a and b.

    2 (a) what tells you the direction that a particle moves ?

    (b) acceleration is the derivative of velocity

    (c) y(t) = \int v(t) \, dt.

    you'll have to use substitution to find the antiderivative and the given initial condition to find the constant of integration.

    (d) total distance = \int_0^2 |v(t)| \, dt
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  4. #4
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    Quote Originally Posted by skeeter View Post
    1. (a) use the facts that f'(-1) = 0 and f''(-2) = 0 to solve for a and b.

    (b) straight forward problem, once you find a and b.

    2 (a) what tells you the direction that a particle moves ?

    (b) acceleration is the derivative of velocity

    (c) y(t) = \int v(t) \, dt.

    you'll have to use substitution to find the antiderivative and the given initial condition to find the constant of integration.

    (d) total distance = \int_0^2 |v(t)| \, dt

    That the problem I do not understand how to use f'(-1) = 0 and f''(-2) = 0 to find critical points.

    for 2 (a) It's veolcity. When the function is bellow the x-axis then it is moving to the left but when it's above then it's moving to the right. That I know.

    Like I'm it's a bit fuzzy because we had this from way back in the year and now he, the teacher, expects us to remember everything.
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  5. #5
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    Quote Originally Posted by MathmaticAvatar View Post
    That the problem I do not understand how to use f'(-1) = 0 and f''(-2) = 0 to find critical points.

    find f'(x) , sub in -1 for x and set = 0 ... you'll get an equation in terms of a and b.

    find f''(x) , sub in -2 for x and set = 0 ... you'll get an equation that you can solve for a

    once you get a , go back and find b.

    find f''(x), sub in -2 for

    for 2 (a) It's veolcity. When the function is bellow the x-axis then it is moving to the left but when it's above then it's moving to the right. That I know.

    ok ... what is the sign of v(1.5) ? how will that answer the question ?
    ...
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