finding equation of tangent line at point (1,6)

y=(x²+2x)(x+1)

i got the derivative to be

f'(x)= 3x²+6x+2

but how do i use this to find the equation of a line at point (1,6)?

(im guessing i could use the y-y=slope(x-x) forumla but im unsure how with this derivative...)

-thx