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Math Help - finding equation of tangent line

  1. #1
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    finding equation of tangent line

    finding equation of tangent line at point (1,6)
    y=(x+2x)(x+1)

    i got the derivative to be
    f'(x)= 3x+6x+2

    but how do i use this to find the equation of a line at point (1,6)?
    (im guessing i could use the y-y=slope(x-x) forumla but im unsure how with this derivative...)

    -thx
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  2. #2
    MHF Contributor Calculus26's Avatar
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    you are correct

    y = m(x-x0) + y0

    m = f '(1) (x0,y0) = (1,6)
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  3. #3
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    z

    ans would be this?

    11x-5?

    i didnt quite understand your reply lol
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  4. #4
    MHF Contributor Calculus26's Avatar
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    that's correct
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  5. #5
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    z

    thx
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