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Math Help - area enclosed by

  1. #1
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    area enclosed by

    r=1+2sin(6θ)

    here's a graph of the equation: http://www.wolframalpha.com/input/?i=polar+1%2B2sin(6x)

    I don't know how to set up the integral
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  2. #2
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    \int
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  3. #3
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    Quote Originally Posted by yoman360 View Post
    \int
    I don't think that was quite his question!

    The area of a circular sector of radius r and angle \theta is [tex]\frac{1}{2}r^2\theta[/itex]. For an "infinitesmal" angle, we can think of the radius of any curve as constant and so the "differential of area", in polar coordinates, is [tex]\frac{1}{2}r^2 d\theta[/itex].

    You want \frac{1}{2}\int_{-\pi}^\pi r^2 d\theta.
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