y = (x²+2x)(x+1) ------------------ f'(x) = 3x²+6x+2 y = 3x-1 ------------------ f'(y) = 3-1 = 2 f'(y) = 2 -thx
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Originally Posted by maybnxtseasn y = (x²+2x)(x+1) ------------------ f'(x) = 3x²+6x+2 y = 3x-1 ------------------ f'(y) = 3-1 = 2 the derivative of -1 is 0 f'(y) = 2 -thx First one is fine. Remember, the derivative of any constant is zero.
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