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Math Help - Integral Question- Am I doing it correctly?

  1. #1
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    Integral Question- Am I doing it correctly?

    I am not sure how to Integrate this type of problems--

    integral squareroot(t^2+t) dt

    and integral (5t^2-6)dt

    Attempts:

    integral sqareroot(t^2+t) dt= 2/3 ((t^2+t) ^(3/2) (2t+1)

    And solve the other one same way.

    Is that right?

    (I am not sure if I differentiate the middle portion when integrating)
    Last edited by skboss; February 11th 2010 at 05:59 PM.
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  2. #2
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    Quote Originally Posted by skboss View Post
    I am not sure how to Integrate this type of problems--

    integral squareroot(t^2+t) dt ... ???

    and integral (5t^2-6)dt

    Attempts:

    integral sqareroot(t^2+1) dt= 2/3 ((t^2+1) ^(3/2) 2t no

    And solve the other one same way.

    Is that right?

    (I am not sure if I differentiate the middle portion when integrating)
    \int \sqrt{t^2+1} \, dt requires a trig substitution.

    \int 5t^2 - 6 \, dt = \frac{5t^3}{3} - 6t + C<br />
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  3. #3
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    Sorry I posted the question wrong. It should be

    integral squareroot(t^2+t) dt
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  4. #4
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    Quote Originally Posted by skboss View Post
    Sorry I posted the question wrong. It should be

    integral squareroot(t^2+t) dt
    you just made it more difficult ...

    use ... Wolfram Mathematica Online Integrator to see the antiderivative.
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  5. #5
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    Haha, sorry. Thanks for the link though.
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