# Thread: area of polar curves

1. ## area of polar curves

find the area of the region that is bounded by the given curve and lies in the specified sector.
r=sin θ , $\frac{\pi}{3}$ ≤ θ ≤ $\frac{2\pi}{3}$

2. Originally Posted by yoman360
find the area of the region that is bounded by the given curve and lies in the specified sector.
r=sin θ , $\frac{\pi}{3}$ ≤ θ ≤ $\frac{2\pi}{3}$
$A = \int_{\theta_1}^{\theta_2} \frac{r^2}{2} \, d\theta
$

3. Originally Posted by skeeter
$A = \int_{\theta_1}^{\theta_2} \frac{r^2}{2} \, d\theta
$
I got

$\frac{\pi}{12} + \frac{\sqrt{3}}{8}$

4. Originally Posted by yoman360
I got

$\frac{\pi}{12} + \frac{\sqrt{3}}{8}$
that works.