# Thread: [SOLVED] Volume of solid obtained by rotsting the bounded region

1. ## [SOLVED] Volume of solid obtained by rotsting the bounded region

Find the volume of the solid obtained by rotating the bounded region in the first quadrant enclosed by the graphs of y=x2, x=y^4 about the x-axis.

Here's what i did:
r1=1+y
r2=sqrt(y)-y^4

2pi 0--1 (1+y)(sqrt(y)-y^4)dy

I integrated this and got 7pi/5 which is incorrect. Are my radii and formula correct? If not, could someone please correct it? Thanks

2. Originally Posted by yzobel
Find the volume of the solid obtained by rotating the bounded region in the first quadrant enclosed by the graphs of y=x2, x=y^4 about the x-axis.

Here's what i did:
r1=1+y
r2=sqrt(y)-y^4

2pi 0--1 (1+y)(sqrt(y)-y^4)dy

I integrated this and got 7pi/5 which is incorrect. Are my radii and formula correct? If not, could someone please correct it? Thanks
I assume it's $\displaystyle y = x^2$

washers w/r to x ...

$\displaystyle V = \pi \int_0^1 \sqrt{x} - x^4 \, dx$