so the two curves are: 12ln(x) and xln(x) I got the bounds to be 1 and 12 so i got the integral between 1 and 12 of 12ln(x)-xln(x) dx. What do I do after this?
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Originally Posted by krnbluemonkey so the two curves are: 12ln(x) and xln(x) I got the bounds to be 1 and 12 so i got the integral between 1 and 12 of 12ln(x)-xln(x) dx. What do I do after this? $\displaystyle 12\ln{x} - x\ln{x} = \ln{x}(12-x)$ $\displaystyle \int \ln{x}(12-x) \, dx$ let $\displaystyle u = \ln{x}$ and $\displaystyle dv = (12-x) \, dx $ you know the rest ... $\displaystyle \int u \, dv = uv - \int v \, du$
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