# Thread: Integration by Trig substitution

1. ## Integration by Trig substitution

Find the integration of :
(x^3)/(sqrt(x^2+100))

I did the following work, but it seems my answer is not matching to the Wolfram|Alpha' answer.

int x^3/(sqrt( x^2 +100)) dx - Wolfram|Alpha

2. Originally Posted by racewithferrari
Find the integration of :
(x^3)/(sqrt(x^2+100))

I did the following work, but it seems my answer is not matching to the Wolfram|Alpha' answer.

int x^3/(sqrt( x^2 +100)) dx - Wolfram|Alpha
it is the same,..just in different form,..try to simplify it

3. Originally Posted by racewithferrari
Find the integration of :
(x^3)/(sqrt(x^2+100))

I did the following work, but it seems my answer is not matching to the Wolfram|Alpha' answer.

int x^3/(sqrt( x^2 +100)) dx - Wolfram|Alpha
Don't use a trig sub, use a hyperbolic sub.

Let $x = 10\sinh{t}$ so that $dx = 10\cosh{t}\,dt$.

Then the integral becomes

$\int{\frac{x^3}{\sqrt{x^2 + 100}}\,dx}$

$= \int{\frac{1000\sinh^3{t}}{\sqrt{(10\sinh{t})^2 + 100}}\,10\cosh{t}\,dt}$

$= \int{\frac{1000\sinh^3{t}}{10\cosh{t}}\,10\cosh{t} \,dt}$

$= \int{1000\sinh^3{t}\,dt}$

$= \int{1000\sinh{t}\sinh^2{t}\,dt}$

$= \int{1000\sinh{t}(\cosh^2{t} - 1)\,dt}$

$= 1000\int{\sinh{t}(\cosh^2{t} - 1)\,dt}$

Let $u = \cosh{t}$ so that $du = \sinh{t}\,dt$

The integral becomes

$1000\int{u^2 - 1\,du}$

$= 1000\left(\frac{1}{3}u^3 - u\right) + C$

Now convert it back to a function of $x$.