Okay so I've ran into another bit of a snag...
I know I can solve by the square and ill get
sqrt(4-(x-2)^(2))
but then again the question looks alot like the derivative of arcsin, which can be changed into arcsin...
What would be best fastest most efficient way of getting there?
Yes. Thank you very much.
However, I'm wondering when your doing that kind of substitution, how do you know that x-2=2sin(u) is equivalent to one another?
I understand that sin(u) would equal x-2 / 2, but where would you get the 2 from to begin with?
Do you assign 2 from x-2 as "a"?
You say that it looked to you like "arcsine". Notice that you could have used either x-1= 2cos(u) or x-1= 2sin(u)- they both give the same result.
You could also argue this way: Factor the "4" out: which should remind you of or so that you can use either or to clear the square root.