Find the Area of a region bounded by graphs of the function
x^2+4, y=-x+4 x=2
I found the integration points to be 0 and 2.
the f(x)-g(x) i am not sure how to determine which is f(x) and which is g(x)
I've done the integral (x^2+4)-(-x+4)=> (x^2+x) integrate (X^3/3+X^2/2)dx
evaluating at 2 => (8/3+2)-(0) = 14/3 is my result?
Is this correct?