consider the expression equal to say t. take logs on both sides of the equation then differentiate and u should get the derivative of t ie. the derivative of your expression.
If $\displaystyle g$ is a differentiable function and $\displaystyle f(x)=e^{g(x)}$, then $\displaystyle f$ is differentiable and:
$\displaystyle f'(x)=e^{g(x)} g'(x)$.
Just apply this on your problem.