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Math Help - Derivative of the function

  1. #1
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    Derivative of the function

    I am having some trouble with this type of problem, here is the work, would someone look it over and let me know where I went wrong.
    Here is the problem:

    g(x) = (1x^2-1x+3)e^x Find g'(x) = ?

    g(x) = e^x*x^2 - e^x*x + 3*e^x
    d/dx[e^x*x^2] + d/dx[-e^x*x] + d/dx[3*e^x] =
    e^x d/dx[x^2] -e^x d/dx[x] +3 d/dx[e^x] =
    2e^x -e^x + 3e^x

    Thankx
    Keith
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  2. #2
    Junior Member frenzy's Avatar
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    Quote Originally Posted by kcsteven View Post
    I am having some trouble with this type of problem, here is the work, would someone look it over and let me know where I went wrong.
    Here is the problem:

    g(x) = (1x^2-1x+3)e^x Find g'(x) = ?

    g(x) = e^x*x^2 - e^x*x + 3*e^x
    d/dx[e^x*x^2] + d/dx[-e^x*x] + d/dx[3*e^x] =
    e^x d/dx[x^2] -e^x d/dx[x] +3 d/dx[e^x] =
    2e^x -e^x + 3e^x

    Thankx
    Keith
    d/dx[(x^2-x+3)e^x]=(x^2-x+3)e^x+(2x-1)e^x
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