# Thread: Derivative of the function

1. ## Derivative of the function

I am having some trouble with this type of problem, here is the work, would someone look it over and let me know where I went wrong.
Here is the problem:

g(x) = (1x^2-1x+3)e^x Find g'(x) = ?

g(x) = e^x*x^2 - e^x*x + 3*e^x
d/dx[e^x*x^2] + d/dx[-e^x*x] + d/dx[3*e^x] =
e^x d/dx[x^2] -e^x d/dx[x] +3 d/dx[e^x] =
2e^x -e^x + 3e^x

Thankx
Keith

2. Originally Posted by kcsteven
I am having some trouble with this type of problem, here is the work, would someone look it over and let me know where I went wrong.
Here is the problem:

g(x) = (1x^2-1x+3)e^x Find g'(x) = ?

g(x) = e^x*x^2 - e^x*x + 3*e^x
d/dx[e^x*x^2] + d/dx[-e^x*x] + d/dx[3*e^x] =
e^x d/dx[x^2] -e^x d/dx[x] +3 d/dx[e^x] =
2e^x -e^x + 3e^x

Thankx
Keith
d/dx[(x^2-x+3)e^x]=(x^2-x+3)e^x+(2x-1)e^x