Hello everyone, I'm new to this forum and to calculus in general too. Can anyone help me expand log(1-x/1+x) as taylor series pls I've been stuck on this problem for quite a while. Thanks very much in advance!
you note that: $\displaystyle
\ln \left( {\frac{{1 - x}}
{{1 + x}}} \right) = \ln \left( {1 - x} \right) - \ln \left( {1 + x} \right)
$, and remeber that $\displaystyle
\sum\limits_{n = 0}^\infty {x^n } = \frac{1}
{{1 - x}}{\text{ }}\forall \left| x \right| < 1{\text{ }}
$