taylor series expansion for log(1-x/1+x)

**zyd** · February 10th 2010, 04:02 PM

Hello everyone, I'm new to this forum and to calculus in general too. Can anyone help me expand log(1-x/1+x) as taylor series pls I've been stuck on this problem for quite a while. Thanks very much in advance!

**Krizalid** · February 10th 2010, 04:08 PM

centered at?

if it is centered at zero, then just remember that $\ln\frac ab=\ln a-\ln b$ and the expansion for $\ln(1-x)$ and in the same fashion for $\ln(1+x).$

**Nacho** · February 10th 2010, 04:09 PM

you note that: $ \ln \left( {\frac{{1 - x}} {{1 + x}}} \right) = \ln \left( {1 - x} \right) - \ln \left( {1 + x} \right) $ , and remeber that $ \sum\limits_{n = 0}^\infty {x^n } = \frac{1} {{1 - x}}{\text{ }}\forall \left| x \right| < 1{\text{ }} $

**zyd** · February 14th 2010, 04:13 AM

Thanks for the help!

Thread: taylor series expansion for log(1-x/1+x)

LinkBack

Thread Tools

Display

taylor series expansion for log(1-x/1+x)

Similar Math Help Forum Discussions

expansion of e^x in Taylor series

Taylor Series Expansion Around 0.25

Taylor series expansion

Taylor Series expansion

Taylor Series Expansion of an eqn

Search Tags