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Math Help - taylor series expansion for log(1-x/1+x)

  1. #1
    zyd
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    taylor series expansion for log(1-x/1+x)

    Hello everyone, I'm new to this forum and to calculus in general too. Can anyone help me expand log(1-x/1+x) as taylor series pls I've been stuck on this problem for quite a while. Thanks very much in advance!
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  2. #2
    Math Engineering Student
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    centered at?

    if it is centered at zero, then just remember that \ln\frac ab=\ln a-\ln b and the expansion for \ln(1-x) and in the same fashion for \ln(1+x).
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  3. #3
    Member Nacho's Avatar
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    you note that: <br />
\ln \left( {\frac{{1 - x}}<br />
{{1 + x}}} \right) = \ln \left( {1 - x} \right) - \ln \left( {1 + x} \right)<br />
, and remeber that <br />
\sum\limits_{n = 0}^\infty  {x^n }  = \frac{1}<br />
{{1 - x}}{\text{ }}\forall \left| x \right| < 1{\text{ }}<br />
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  4. #4
    zyd
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    Thanks for the help!
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