$\displaystyle
\int_{0}^{2} \frac{1}{\sqrt{256 +x^2}} dx
$
Any suggestion on how to truck though this?
k so I have $\displaystyle
\displaystyle{\frac{1}{\sqrt{256+16\tan\!\left(u^{ 2}\right)}}\frac{du}{16\sec^{2}\!\left(u\right)}}
$
where do I go from that?
Sorry if i dont respond right away, my laptops about to die and I have a chemistry seminar for the next hour just been trying to get some math done while I wait
$\displaystyle
\displaystyle{\ln\!\left(\left|\tan\!\left(u\right )+\sec\!\left(u\right)\right|\right)}
$
And now I'm utterly lost how to sub back u in... I would assume u=tan^(-1)(x)/(16)... but what do I do with something like that...?
This question looked so harmless to begin with...