Ok, so here is the equation:

$\displaystyle g(x) = (\arccos (x^{2}))^{5}$

I know that $\displaystyle \arccos(x) = \frac{-1}{\sqrt{1-x^{2}}}$

We use that for taking the integral of $\displaystyle \arccos(x)$, but to do for the derivative?

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- Feb 10th 2010, 11:09 AMTheMathThamtaking the derivative of trig functions
Ok, so here is the equation:

$\displaystyle g(x) = (\arccos (x^{2}))^{5}$

I know that $\displaystyle \arccos(x) = \frac{-1}{\sqrt{1-x^{2}}}$

We use that for taking the integral of $\displaystyle \arccos(x)$, but to do for the derivative? - Feb 10th 2010, 11:17 AMicemanfan
You cannot integrate the inverse cosine. To calculate the derivative, use the chain rule:

$\displaystyle g'(x) = 5(\arccos (x^2))^4 * \frac{d}{dx} (\arccos (x^2))$ - Feb 10th 2010, 12:06 PMTheMathTham