Originally Posted by Awsom Guy so I get: C=0 and: 8=4a^2-2b+C How can I simultanously solve this. Come on, you have $\displaystyle 4a^2 - 2b + c = 8$ and you know that $\displaystyle b = 4a$ and $\displaystyle c = 0$. What's the equation you get when you substitute $\displaystyle b$ and $\displaystyle c$?
Follow Math Help Forum on Facebook and Google+
oh yessss thanks I already had that but my eyes are closing tired and yess I forgot that you used a instead of x. wow I should get some sleep now, thank you sooooo much, most appreciated. thanks
View Tag Cloud