At what point on the given curve is the tangent line parallel to the line 3x - y = 2? y = 3 + 2ex − 5x How do i do this?
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Originally Posted by rhcp1231 At what point on the given curve is the tangent line parallel to the line 3x - y = 2? y = 3 + 2ex − 5x How do i do this? You need to set the derivative of the curve to the slope of the given line and solve for x. By the way is 2e^x or 2ex?
2e^x so the derivative is 2e^x-5, how do i solve for x for that?
Originally Posted by rhcp1231 2e^x so the derivative is 2e^x-5, how do i solve for x for that? Then just plug that into the original equation for the curve and you have the point where te tangent line is parallel to the given line.
Originally Posted by Keithfert488 and the 3 comes from 3x - y = 2 right?
Originally Posted by rhcp1231 and the 3 comes from 3x - y = 2 right? Yes. If you put the equation into slope intercept format (y=mx+b) you find that y=3x-2 so the slope is three.
Originally Posted by Keithfert488 Yes. If you put the equation into slope intercept format (y=mx+b) you find that y=3x-2 so the slope is three. sweet thanks for the help
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