Find an equation of the tangent line to the curve at the given point.

24 + 4x2 − 7x, (1, -1)x

I know i would need to use m = limf(x)-f(a)

x->ax-abut then i have lim

2x^4+4x^2-7x-1

x->1 x-1

i am not quite sure how to factor that limit so i can cancel the x-1 and get a equation that i can plug my x=1 value into and get my slope so i can use the formula:

y-h = m(x-a)