Math Help - Work...

1. Work...

I am having a hard time seeing where to go with this. I dont need the answer as I already ahve it since its a practice test. But I would like to see how you set it up and work it....

Thanks,
Caleb

2. Originally Posted by cmr7
I am having a hard time seeing where to go with this. I dont need the answer as I already ahve it since its a practice test. But I would like to see how you set it up and work it....

Thanks,
Caleb
work = integral of (weight density)(cross-sectional area of a representative slab of water)(lift distance)(slab thickness)

$W = 62.5\pi \int_0^8 \left(\frac{y^2}{16}\right)(12-y) \, dy
$