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Math Help - Work...

  1. #1
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    Work...

    I am having a hard time seeing where to go with this. I dont need the answer as I already ahve it since its a practice test. But I would like to see how you set it up and work it....



    Thanks,
    Caleb
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  2. #2
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    Quote Originally Posted by cmr7 View Post
    I am having a hard time seeing where to go with this. I dont need the answer as I already ahve it since its a practice test. But I would like to see how you set it up and work it....



    Thanks,
    Caleb
    work = integral of (weight density)(cross-sectional area of a representative slab of water)(lift distance)(slab thickness)

    W = 62.5\pi \int_0^8 \left(\frac{y^2}{16}\right)(12-y) \, dy<br />
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