# Work...

• Feb 9th 2010, 02:51 PM
cmr7
Work...
I am having a hard time seeing where to go with this. I dont need the answer as I already ahve it since its a practice test. But I would like to see how you set it up and work it....

http://i221.photobucket.com/albums/d...cticetest2.jpg

Thanks,
Caleb
• Feb 9th 2010, 03:18 PM
skeeter
Quote:

Originally Posted by cmr7
I am having a hard time seeing where to go with this. I dont need the answer as I already ahve it since its a practice test. But I would like to see how you set it up and work it....

http://i221.photobucket.com/albums/d...cticetest2.jpg

Thanks,
Caleb

work = integral of (weight density)(cross-sectional area of a representative slab of water)(lift distance)(slab thickness)

$W = 62.5\pi \int_0^8 \left(\frac{y^2}{16}\right)(12-y) \, dy
$