When Y = t^3 – 3t, and X = t^2 + t What is differential d^2y/dx^2= ?
Last edited by javad1983; Feb 9th 2010 at 06:55 AM.
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dy/dx = (dy/dt)/(dx/dt) = (3t^2 -3)/(2t+1)
d^2 (y)/dx^2 = d(dy/dx)/dx = [d(dy/dx)/dt] / [dx/dt]
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