I need to derive defined integral which does look like this... $\displaystyle F(x)=\int_0^x{\frac{\cos t}{1+t^2}dt}$ $\displaystyle F'(x)=?$
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Thankyou... how can i get left and right limit of this derivate function? $\displaystyle \frac{dF}{dx}=F'(x)=\frac{\cos t}{1+t^2}$
Not not quite right F ' (x) = cos(x)/(1+x^2) here we have x not t
Forgot to change t to x thankyou.
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