I need to derive defined integral which does look like this...

$\displaystyle F(x)=\int_0^x{\frac{\cos t}{1+t^2}dt}$

$\displaystyle F'(x)=?$

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- Feb 9th 2010, 04:17 AMPJaniDeriving defined Integral
I need to derive defined integral which does look like this...

$\displaystyle F(x)=\int_0^x{\frac{\cos t}{1+t^2}dt}$

$\displaystyle F'(x)=?$ - Feb 9th 2010, 04:34 AMCalculus26
See attachment

- Feb 9th 2010, 06:51 AMPJani
Thankyou...

how can i get left and right limit of this derivate function?

$\displaystyle \frac{dF}{dx}=F'(x)=\frac{\cos t}{1+t^2}$ - Feb 9th 2010, 06:57 AMCalculus26
Not not quite right

F ' (x) = cos(x)/(1+x^2) here we have x not t - Feb 9th 2010, 07:00 AMPJani
Forgot to change t to x thankyou.