# Deriving defined Integral

• February 9th 2010, 04:17 AM
PJani
Deriving defined Integral
I need to derive defined integral which does look like this...

$F(x)=\int_0^x{\frac{\cos t}{1+t^2}dt}$

$F'(x)=?$
• February 9th 2010, 04:34 AM
Calculus26
See attachment
• February 9th 2010, 06:51 AM
PJani
Thankyou...

how can i get left and right limit of this derivate function?

$\frac{dF}{dx}=F'(x)=\frac{\cos t}{1+t^2}$
• February 9th 2010, 06:57 AM
Calculus26
Not not quite right

F ' (x) = cos(x)/(1+x^2) here we have x not t
• February 9th 2010, 07:00 AM
PJani
Forgot to change t to x thankyou.