I am new to anti differentiation and I need help with this question. =4t-3/t^2 This is my attempt: 4t^2/2 + 1/3t + C 2t^2 + 1/3t + C I am having problems with the second bit ( 1/3t ) The answer is 2t^2 + 3/t + C Thanks
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Originally Posted by Awsom Guy I am new to anti differentiation and I need help with this question. =4t-3/t^2 This is my attempt: 4t^2/2 + 1/3t + C 2t^2 + 1/3t + C I am having problems with the second bit ( 1/3t ) The answer is 2t^2 + 3/t + C Thanks Please either use brackets where they're needed or use LaTeX. Is your function $\displaystyle \frac{4t-3}{t^2}$ or $\displaystyle 4t - \frac{3}{t^2}$?
I am sorry I am not sure how to use that program I will use brackets next time but it is the second one: (4t) - (3/t^2)
Originally Posted by Awsom Guy I am sorry I am not sure how to use that program I will use brackets next time but it is the second one: (4t) - (3/t^2) $\displaystyle \int{4t - \frac{3}{t^2}\,dt} = \int{4t - 3t^{-2}\,dt}$ $\displaystyle = \frac{4t^2}{2} - \frac{3t^{-1}}{-1} + C$ $\displaystyle = 2t^2 + \frac{3}{t} + C$.
Thanks again, I have done the question I just needed thaty little small step
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