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Math Help - Anti-Differentiation

  1. #1
    Member Awsom Guy's Avatar
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    Anti-Differentiation

    I am new to anti differentiation and I need help with this question.

    =4t-3/t^2

    This is my attempt:

    4t^2/2 + 1/3t + C
    2t^2 + 1/3t + C

    I am having problems with the second bit ( 1/3t )

    The answer is 2t^2 + 3/t + C

    Thanks
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  2. #2
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    Quote Originally Posted by Awsom Guy View Post
    I am new to anti differentiation and I need help with this question.

    =4t-3/t^2

    This is my attempt:

    4t^2/2 + 1/3t + C
    2t^2 + 1/3t + C

    I am having problems with the second bit ( 1/3t )

    The answer is 2t^2 + 3/t + C

    Thanks
    Please either use brackets where they're needed or use LaTeX.

    Is your function \frac{4t-3}{t^2} or 4t - \frac{3}{t^2}?
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  3. #3
    Member Awsom Guy's Avatar
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    I am sorry I am not sure how to use that program I will use brackets next time but it is the second one: (4t) - (3/t^2)
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  4. #4
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    Quote Originally Posted by Awsom Guy View Post
    I am sorry I am not sure how to use that program I will use brackets next time but it is the second one: (4t) - (3/t^2)
    \int{4t - \frac{3}{t^2}\,dt} = \int{4t - 3t^{-2}\,dt}

     = \frac{4t^2}{2} - \frac{3t^{-1}}{-1} + C

     = 2t^2 + \frac{3}{t} + C.
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  5. #5
    Member Awsom Guy's Avatar
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    Thanks again, I have done the question I just needed thaty little small step
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