# Anti-Differentiation

• Feb 8th 2010, 10:59 PM
Awsom Guy
Anti-Differentiation
I am new to anti differentiation and I need help with this question.

=4t-3/t^2

This is my attempt:

4t^2/2 + 1/3t + C
2t^2 + 1/3t + C

I am having problems with the second bit ( 1/3t )

The answer is 2t^2 + 3/t + C

Thanks
• Feb 8th 2010, 11:06 PM
Prove It
Quote:

Originally Posted by Awsom Guy
I am new to anti differentiation and I need help with this question.

=4t-3/t^2

This is my attempt:

4t^2/2 + 1/3t + C
2t^2 + 1/3t + C

I am having problems with the second bit ( 1/3t )

The answer is 2t^2 + 3/t + C

Thanks

Please either use brackets where they're needed or use LaTeX.

Is your function $\displaystyle \frac{4t-3}{t^2}$ or $\displaystyle 4t - \frac{3}{t^2}$?
• Feb 8th 2010, 11:07 PM
Awsom Guy
I am sorry I am not sure how to use that program I will use brackets next time but it is the second one: (4t) - (3/t^2)
• Feb 8th 2010, 11:11 PM
Prove It
Quote:

Originally Posted by Awsom Guy
I am sorry I am not sure how to use that program I will use brackets next time but it is the second one: (4t) - (3/t^2)

$\displaystyle \int{4t - \frac{3}{t^2}\,dt} = \int{4t - 3t^{-2}\,dt}$

$\displaystyle = \frac{4t^2}{2} - \frac{3t^{-1}}{-1} + C$

$\displaystyle = 2t^2 + \frac{3}{t} + C$.
• Feb 8th 2010, 11:15 PM
Awsom Guy
Thanks again, I have done the question I just needed thaty little small step :)