If a ball is given a push so that it has an initial velocity of 5 m/s down a certain inclined plane, then the distance it rolled arter t seconds is s = 5t + 3t^2.
a) Find the velocity after 2 seconds?
v(t) = 5 + 6t
v(2) = 5 + 6(2)
V(2) = 17
b) How long does it take for the velocity to reach 35 m/s?
35 = 5 + 6t
-5 -5
30 = 6t
so I divided 30/6 = 6t/6
5 seconds
Am I right?


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