If a ball is given a push so that it has an initial velocity of 5 m/s down a certain inclined plane, then the distance it rolled arter t seconds is s = 5t + 3t^2.

a) Find the velocity after 2 seconds?

v(t) = 5 + 6t

v(2) = 5 + 6(2)

V(2) = 17

b) How long does it take for the velocity to reach 35 m/s?

35 = 5 + 6t

-5 -5

30 = 6t

so I divided 30/6 = 6t/6

5 seconds

Am I right?