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Math Help - converge or diverge

  1. #1
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    converge or diverge

    1/((n^2-1)^1/n)
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  2. #2
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    Quote Originally Posted by nzm88 View Post
    1/((n^2-1)^1/n)
    Draw a conclusion from this: find limit of 1/((n^2-1)^1/n) as n approaches infinity - Wolfram|Alpha
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