# Thread: Determining convergence or divergence of a series

1. ## Determining convergence or divergence of a series

determine this series converge or diverges

summation(n^(1/2)/(n^2-3))

2. Originally Posted by nzm88
determine this series converge or diverges

summation(n^(1/2)/(n^2-3))
$\frac{\sqrt{n}}{n^2-3}\underset{n\to\infty}{\sim}\frac{1}{n^{\frac{3}{ 2}}}$...so