Results 1 to 2 of 2

Math Help - Determining convergence or divergence of a series

  1. #1
    Newbie
    Joined
    Aug 2009
    Posts
    11

    Determining convergence or divergence of a series

    determine this series converge or diverges

    summation(n^(1/2)/(n^2-3))
    Last edited by mr fantastic; February 8th 2010 at 09:05 PM. Reason: Changed post title
    Follow Math Help Forum on Facebook and Google+

  2. #2
    MHF Contributor Drexel28's Avatar
    Joined
    Nov 2009
    From
    Berkeley, California
    Posts
    4,563
    Thanks
    21
    Quote Originally Posted by nzm88 View Post
    determine this series converge or diverges

    summation(n^(1/2)/(n^2-3))
    \frac{\sqrt{n}}{n^2-3}\underset{n\to\infty}{\sim}\frac{1}{n^{\frac{3}{  2}}}...so
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Determining series convergence or divergence
    Posted in the Calculus Forum
    Replies: 4
    Last Post: April 3rd 2010, 08:55 PM
  2. Determining convergence or divergence
    Posted in the Calculus Forum
    Replies: 2
    Last Post: March 5th 2010, 07:26 PM
  3. Convergence, Divergence of a series
    Posted in the Calculus Forum
    Replies: 1
    Last Post: September 20th 2009, 01:44 PM
  4. Determining Convergence or Divergence
    Posted in the Calculus Forum
    Replies: 4
    Last Post: July 6th 2008, 07:52 PM
  5. Replies: 2
    Last Post: July 9th 2007, 06:23 PM

Search Tags


/mathhelpforum @mathhelpforum