# Determining convergence or divergence of a series

• February 8th 2010, 08:55 PM
nzm88
Determining convergence or divergence of a series
determine this series converge or diverges

(Bow)summation(n^(1/2)/(n^2-3))
• February 8th 2010, 09:15 PM
Drexel28
Quote:

Originally Posted by nzm88
determine this series converge or diverges

(Bow)summation(n^(1/2)/(n^2-3))

$\frac{\sqrt{n}}{n^2-3}\underset{n\to\infty}{\sim}\frac{1}{n^{\frac{3}{ 2}}}$...so