Hey guys, I need some help with a question. I've tried to do it but I keep getting it wrong.

Here's the original question:

Find an equation of the tangent line to the curve at the given point.

And here's my attempt:

Tried using the quotient rule to find the slope since the derivative of the equation is the slope:

(gx)(f'x)-(fx)(g'x) / (gx)^2

(x+1)^2(3) - (3x)(2x+2) / (x+1)^4

(x^2+2x+1)(3) - (6x^2+6x) / (x+1)^4

(3x^2+6x+3) - (6x^2+6x) / (x+1)^4

(-3x^2+12x+3) / (x+1)^4 >> from this point on I wasn't sure what to do and got stuck....any help is appreciated!

Thanks,

Grace