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Math Help - Derivative

  1. #1
    VkL
    VkL is offline
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    Derivative

    What is the derivative?

    f(x) = 5 ^ [(x^2)-(2x)+8]

    is this correct>

    f ' (x) = 5 ^ {[(x^2)-(2x)] * ln(5) * 2x-2 } * 5^8

    ?
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  2. #2
    Junior Member
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    \frac{d}{dx}5^{x^2-2x+8}=5^{x^2-2x+8}ln(5)(2x-2)

    The derivative of a constant raised to a function = the same constant raised to the same function times the natural log of the base times the derivative of the function which is in the exponent.

    Edit: I think your answer is okay too, I don't see any reason you couldn't split that up into 5^{x^2-2x}(5^8) which would give you the answer that you got. To simplify your answer, you would just end up adding the 5^8 back into the 5^{x^2-2x} which would be the same as what is up top.
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