Results 1 to 2 of 2

Math Help - Find the slope of the curve (derive) ln(x^2+1) at point (0,0)

  1. #1
    Newbie
    Joined
    Feb 2010
    Posts
    9

    Find the slope of the curve (derive) ln(x^2+1) at point (0,0)

    This is what I have so far for the problem: derive ln(x^2+1) at (0,0)

    y=ln(u) u=x^2+1

    y=1/x(u)*2x

    y=1/x(x^2+1)*2x

    y=2(x^2+1)

    0=2(x^2+1)

    0=(x^2+1)

    I'm not sure how to factor x^2+1. I was wondering if i'm doing this problem correctly. If so, should I just use the quadratic equation for that? I think that I may get an imaginary number.

    Thanks! This forum seems legit.

    -star
    Follow Math Help Forum on Facebook and Google+

  2. #2
    MHF Contributor
    skeeter's Avatar
    Joined
    Jun 2008
    From
    North Texas
    Posts
    12,109
    Thanks
    976
    Quote Originally Posted by starbless View Post
    This is what I have so far for the problem: derive ln(x^2+1) at (0,0)

    y=ln(u) u=x^2+1

    y=1/x(u)*2x

    y=1/x(x^2+1)*2x

    y=2(x^2+1)

    0=2(x^2+1)

    0=(x^2+1)

    I'm not sure how to factor x^2+1. I was wondering if i'm doing this problem correctly. If so, should I just use the quadratic equation for that? I think that I may get an imaginary number.

    Thanks! This forum seems legit.

    -star
    \frac{d}{dx} [\ln{u}] = \frac{1}{u} \cdot \frac{du}{dx}

    \frac{d}{dx} [\ln(x^2+1)] = \frac{1}{x^2+1} \cdot 2x = \frac{2x}{x^2+1}
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Slope of a curve at a point
    Posted in the Pre-Calculus Forum
    Replies: 2
    Last Post: September 14th 2011, 10:53 AM
  2. Linear Problem - Slope of Curve Through Point
    Posted in the Differential Equations Forum
    Replies: 2
    Last Post: September 13th 2011, 11:56 AM
  3. Replies: 2
    Last Post: November 5th 2010, 02:34 PM
  4. Replies: 1
    Last Post: January 26th 2009, 06:13 PM
  5. How To Find The Slope Of A Curve...?
    Posted in the Calculus Forum
    Replies: 3
    Last Post: October 15th 2008, 10:44 PM

Search Tags


/mathhelpforum @mathhelpforum