$\displaystyle \displaystyle \int \frac{1}{\sqrt{x^2-2x}} \ dx$ Can someone help?
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How about complete the square in the radical then do one of those trig substitutions on (x-a)^2+b right?
Originally Posted by shawsend How about complete the square in the radical then do one of those trig substitutions on (x-a)^2+b right? Thank you.
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