# How do I find this integral?

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• Feb 7th 2010, 06:03 AM
Josh146
How do I find this integral?
$\displaystyle \int \frac{1}{\sqrt{x^2-2x}} \ dx$

Can someone help?
• Feb 7th 2010, 06:11 AM
shawsend
How about complete the square in the radical then do one of those trig substitutions on (x-a)^2+b right?
• Feb 7th 2010, 06:16 AM
Josh146
Quote:

Originally Posted by shawsend
How about complete the square in the radical then do one of those trig substitutions on (x-a)^2+b right?

Thank you.