Hi,
I have the following equation:
ln(8y)+6xy=ln(sin(4x))
After differentiating I get:
(1/8y)(dy/dx)+6y+6x*(dy/dx)=(4cos(4x))/sin(4x)
And with this, I need to work out dy/dx at (0,0)
When I try this it seems messy and I get zero. Can someone explain where I have gone wrong please
Many thanks