1. find tangent lines

given

$y=x^2$ and $y=-x^2+6x-5$

I know the derivatives are $2x$ and $-2x+6$

how are the equations of 2 tangent lines found to both graphs

the answers are: $y=2x-1$ and $y=4x-4$

2. Originally Posted by bigwave
given

$y=x^2$ and $y=-x^2+6x-5$

I know the derivatives are $2x$ and $-2x+6$

how are the equations of 2 tangent lines found

the answers are: $y=2x-1$ and $y=4x-4$
Hi

The equation of the tangent line at a point whose abscissa is $x_0$ is
$y = f'(x_0)(x-x_0) + f(x_0)$

$f(x)=x^2$
$f'(x)=2x$
The equation of the tangent line at the point whose abscissa is $x_0 = 1$ is
$y = f'(1)(x-1) + f(1)$
$y = 2(x-1) + 1$
$y = 2x-1$

3. Originally Posted by bigwave
given

$y=x^2$ and $y=-x^2+6x-5$

I know the derivatives are $2x$ and $-2x+6$

how are the equations of 2 tangent lines found

the answers are: $y=2x-1$ and $y=4x-4$
1. You have the parabolas:

$p: y = x^2$
and
$q: y = -x^2+6x-5$

2. Let P(p, p²) denote the tangent point on the parabola p and Q(q, -q²+6q-5) the tangent point on the parabola q.

3. The tangent to p at P has the equation:

$t_p: y = 2px - p^2$
and the tangent to q at Q has the equation

$t_q: y = (-2q+6)x +q^2-5$

4. Both equations describe the same line. Thus

$\left|\begin{array}{rcl}2p&=&-2q+6 \\p^2+q^2&=&5 \end{array}\right.$

5. Solve this system of simultaneous equations for p and q. Resubstitute the result into the equations of $t_p$ and $t_q$.

6. For confirmation: Draw the 2 parabolas and the tangents.

4. Originally Posted by running-gag
Hi

The equation of the tangent line at a point whose abscissa is $x_0$ is
$y = f'(x_0)(x-x_0) + f(x_0)$

$f(x)=x^2$
$f'(x)=2x$
The equation of the tangent line at the point whose abscissa is $x_0 = 1$ is
$y = f'(1)(x-1) + f(1)$
$y = 2(x-1) + 1$
$y = 2x-1$
where did you get abscissa is $x_0 = 1$

5. Originally Posted by bigwave
given

$y=x^2$ and $y=-x^2+6x-5$

I know the derivatives are $2x$ and $-2x+6$

how are the equations of 2 tangent lines found

the answers are: $y=2x-1$ and $y=4x-4$
Here's a tip- in the future tell us what the problem really says! Here, you have never said exactly which tangent lines you want to find. Every graph has an infinite number of tangent lines.

I suspect that the problem is asking for lines that at tangent to both of these graphs. Suppose y= mx+ b is the equation of such a tangent line. At the point, $(x_0, y_0)$ where that line is tangent to $y= x^2$ we must have $y_0= x_0^2= mx_0+ b$ and $y'= 2x_0= m$. At the point, $(x_1, y_1)$ where it is tangent to $x^2+ 6x- 5$, we must have $y_1= x_1^2+ 6x_1- 5= mx_1+ b$ and $y'= 2x_1+ 6= m$ so we have 4 equations to solve for m, b, $x_1$, and $x_2$

6. yes the 2 tangent lines would be tangent to both graphs.

it was baffeling to determine the slope of the 2 lines just based on the derivatives and not knowing the points of contact..