Hi,
Can anyone explain how I can find dy/dx of the following:[
8Ye^(6XY)]=sin(4x)
Many thanks
Bryn
I can't seem to proceed easily,
The answer I have worked out is as follows:
(1/8y)(dy/dx)+6y+6x*(dy/dx)=(4cos(4x))/sin(4x)
Using this the question asks me to find the value of dy/dx at the coordinates (0,0).
I found this to be 0 which it seems is wrong, can someone explain to me why this is?
Many thanks